8x^3(6x^2-6x+4)=

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Solution for 8x^3(6x^2-6x+4)= equation:


Simplifying
8x3(6x2 + -6x + 4) = 0

Reorder the terms:
8x3(4 + -6x + 6x2) = 0
(4 * 8x3 + -6x * 8x3 + 6x2 * 8x3) = 0
(32x3 + -48x4 + 48x5) = 0

Solving
32x3 + -48x4 + 48x5 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '16x3'.
16x3(2 + -3x + 3x2) = 0

Ignore the factor 16.

Subproblem 1

Set the factor 'x3' equal to zero and attempt to solve: Simplifying x3 = 0 Solving x3 = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + -3x + 3x2)' equal to zero and attempt to solve: Simplifying 2 + -3x + 3x2 = 0 Solving 2 + -3x + 3x2 = 0 Begin completing the square. Divide all terms by 3 the coefficient of the squared term: Divide each side by '3'. 0.6666666667 + -1x + x2 = 0 Move the constant term to the right: Add '-0.6666666667' to each side of the equation. 0.6666666667 + -1x + -0.6666666667 + x2 = 0 + -0.6666666667 Reorder the terms: 0.6666666667 + -0.6666666667 + -1x + x2 = 0 + -0.6666666667 Combine like terms: 0.6666666667 + -0.6666666667 = 0.0000000000 0.0000000000 + -1x + x2 = 0 + -0.6666666667 -1x + x2 = 0 + -0.6666666667 Combine like terms: 0 + -0.6666666667 = -0.6666666667 -1x + x2 = -0.6666666667 The x term is -1x. Take half its coefficient (-0.5). Square it (0.25) and add it to both sides. Add '0.25' to each side of the equation. -1x + 0.25 + x2 = -0.6666666667 + 0.25 Reorder the terms: 0.25 + -1x + x2 = -0.6666666667 + 0.25 Combine like terms: -0.6666666667 + 0.25 = -0.4166666667 0.25 + -1x + x2 = -0.4166666667 Factor a perfect square on the left side: (x + -0.5)(x + -0.5) = -0.4166666667 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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